find no.of 6&7 letter palindromes that can be formed using the letters of the word EQUATION?
Answers
Answer: 17576
Step-by-step explanation:
Number of 5 lettered palindrome
1
st
digit takes 26
2
nd
digit takes 26
3
rd
digit takes 26
4
th
digit takes 2
nd
digit and
5
th
digit takes 1
st
digit
So, 5 letter palindrome can be formed=26×26×26
=17576
Concept:
According to the multiplication principle, if an event A can happen in x different ways and an event B can happen in y different ways, then there are x y possibilities for both events to happen at once.
Take a look at an illustration of a person who runs a necktie-sewing business. Based on the elements of colour, form, and design, he may create ties that are distinctive. Let's say he gets an option of 4 different design patterns, 3 shapes, and 5 colours. It becomes difficult to calculate how many distinct ties he can form using the conventional counting method. (Let's say the person can create 4 patterns of ties, one for each form, using the colour red. Three shapes exist. Thus, for just red, 4 + 4 + 4 = 12 ties.) For lesser numbers, the old method could appear to be simple. However, it is more difficult than it seems to have more possible outcomes for each occurrence.In this instance, the number of ties that can be formed using the available combinations is determined using the definition of the Fundamental Principle of Counting as follows:
The sum of the unique ties is equal to 5 x 3 x 4 = 60.
Given:
EQUATION
Find:
Find no.of 6&7 letter palindromes that can be formed using the letters of the word EQUATION?
Solution:
6 letter palindrome words will have same 3 letters in beginning, as in the end
7 letter plaindrome words will have same 3 letters, in the beginning, as in the end, the 4th letter can be any letter.
NO. of letters in EQUATION=8
Using fundamental principles of counting,
NO.of 3 letter words =8x8x8
=512
N0. of 7 letter words=8x8x8x8
=4096
Therefore. 6letter palindrome words are =512 and 7 letter palindrome words are =4096
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