Question

find no .of atom of C,H,O present in 3.42gm of sucrore(C12H22O11​

Answer 1

The molecular mass of C12H22O11 is 342 g. So this mass contains the avagadro number of 6.022×10^23 atoms.

The given mass is 3.42 g. Therefore the atoms present in this mass is (6.022×10^23)/100=6.022×10^21 atoms. so the each number of C, H and O is these many.