Question

Find no. Of bricks required to build a wall 22.5 m long 33 m thick and 10 mm hight the brick is 22 × 15 × 9 mm and 1/10 part is field with cement.

Answer 1

Correct Question

$\implies$ Find the number Of bricks required to build a wall 22.5 m long 33 cm thick and 10 m hight. The brick is 22 × 15 × 9 cm and 1/10 part is field with cement.

$\boxed{ Answer= 22,500 Bricks}$

Sol.

$length \: of \: wall \: = 22.5 \: or \: \: \frac{225}{10} \: m \\ breadth \: or \: thickness \: \: of \: wall \: = 10 \: m \\ height \: of \: 33 \: cm \: or \: = \frac{33}{100} m$

Volume of wall = length × breadth × height

$= \frac{225}{10} \times 10 \times \frac{33}{100} = \frac{297}{4} \: \: \: ....(1) \\\\\frac{1}{10} \: portion \: of \: wall \: field \: with \: cement \: = \frac{297}{4} \times \frac{1}{10} = \frac{29.7}{4} \: \: \: .....(2) \\\\from \: equation \: (1) \: and \: (2) \: we \: get \: \\\\ \implies \: Remaining \: wall \: = \frac{297}{4} - \frac{29.7}{4} = \frac{267.3}{4} \: m \\\\ \implies \: Volume \: of \: 1 \: brick \: = \frac{22}{100} \times \frac{15}{100} \times \frac{9}{100} = \frac{297}{100000} \\\\ \implies \: Bricks \: required = \frac{volume \: of \: wall}{volume \: of \: brick} = \frac{2673}{100} \times \frac{1000000}{297} \\\\ \implies \: \boxed{ 22,500\: Bricks}$