Find no of digits in N = 2¹⁰⁰×5²⁰⁰where (log2=0.3010)
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Answer:
log2000
2000
=2000log2000=2000log(2×10
3
)
=2000[log2+3log10]
=2000[0.30103+(3×1)]
=6602.06
x=6602.06
When we take log with base 10, integer in answer shows one less than number of digits in number.
So, number of digits in number 2000
2000
=6602+1=6603
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