Math, asked by attrishivam397, 5 months ago

find number of diagonals of regular Octavian.

Answers

Answered by hearhackerakshitha2

5

Answer:

an octagon has 8(8−3)/2 = 8×5/2 = 20 diagonals.

Answered by kumudajyotisarada

0

an octagon has 8(8−3)/2 = 8×5/2 = 20 diagonals.

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