Find number of terms in AP whose first and last term are 12 and 8 respectively and sum of all the terms is 120.
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a=12, l=8, Sum=120, n=?
sum=n/2(a+l)
120=n/2(12+8)
120=n/2(20)
20n=240
n=240/20
n=12
no. of terms=12
sum=n/2(a+l)
120=n/2(12+8)
120=n/2(20)
20n=240
n=240/20
n=12
no. of terms=12
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