Find number of terms in following sequencs 18, 31/2,13,..-47
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Answer:
Step-by-step explanation:
The given AP is
18,\frac{31}{2},13,...,-47
Here the first term is 18 and the common difference is
\frac{31}{2}-18=\frac{31-36}{2}=\frac{-5}{2}=-2.5
The nth term of an AP is
a_n=a+(n-1)d
-47=18+(n-1)(-2.5)
-47=18-2.5n+2.5
-47=21.5-2.5n
-47-20.5=-2.5n
-67.5=-2.5n
Divide both sides by -2.5.
27=n
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