Find number of terms in given series 3,6,12,24,......,384
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a= 3, d=3, n=?, an=384
an= a+(n-1) d
384 = 3+(n-1) 3
381=(n-1) 3
127=n-1
n=128
an= a+(n-1) d
384 = 3+(n-1) 3
381=(n-1) 3
127=n-1
n=128
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