find number of terms in the AP 2,5,8 ...........119
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Given:
- 2,5,8,...........,119 are in AP
- Number of terms, n=?
Formula:
tn=a+(n-1)d
Solution:
From the given, we get
- a = 2 - - - - >(1)
- a + d = 5 - - - - >(2)
Sub a=2 in eq (2)
(2) => 2+d=5
d=5-2
d=3
- Last term, tn = 119
To find n
Sub a=2, d=3, tn=119 in the formula
tn = a + (n-1)d
119 = 2 + (n-1)3
119 = 2 + 3n - 3
119 = 3n - 1
3n = 119 + 1
3n = 120
n = 120/3
n = 40
Hope this solution will solve your problem
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