find number of zeros that f(x) = (x-2)2 + 4 have
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Answered by
2
Heya!!Here is your answer friend ⤵⤵
(x-2)^2 +4
x^2+4-4x+4=0
x^2-4x+8=0
Now the given equation has highest degree=2
So number of zeroes =2
Hope it helps you ✌✌
(x-2)^2 +4
x^2+4-4x+4=0
x^2-4x+8=0
Now the given equation has highest degree=2
So number of zeroes =2
Hope it helps you ✌✌
Answered by
2
this equation is of degree 2......
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