Question

find of mid of the following frequency distribution table class interval and frequency​

Answer 1

Answer:

Step-by-step explanation:

first we'll find the cumulative frequency of the the given frequency :

6  14  29  39  45  50  

hence total number of students, n = 50 , which is odd.

Median = n +1 /2 th observation = 50 + 1 /2 = 25.5

median = 15.