Question

find one of the root x^3-x^2+x-1=0​

Answer 1

ANSWER

x^3-x^2+x-1=0

f(0)=−1

f(−1)=1

f(−2)=−1

f(−3)=−13

f(−4)=−71

As f(−1)>0 and f(−2)<0

Therefore one roots lies between −2 and −1.

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Answer 2

Answer:

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