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23x−29y=98⟶(i)
29x−23y=110⟶(ii)
Adding (i) and (ii) we get ,
52x−52y=208
⇒52(x−y)=208
⇒x−y=4⟶(iii)
Substracting (ii) from (i),
−6x−6y=−12
⇒x+y=2⟶(iv)
Now by solving (iii) and (iv),
2x=6
⇒x=3
Substituting value of x in equation (iv),
3+y=2
y=−1
∴x=3 and y=−1
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