Question

Find out ( A + B + C + D ) such that AB x CD = DDD, where AB & CB are two digit numbers & DDD is three digits number.

Answer 1

given     A  B
          X C  D
          ______
             DDD
the value of D  could be anything from 1 to 9
if D=1 DDD=111
D=2 DDD=222 and so on. 
if we would take A=3, B=7, C=1, D=5
then DDD=555
so A+B+C+D= 3+7+1+5=16