Question

find out energy of photo of light of wavlenght 6000A.

Answer 1

Answer: 2.067 eV

Or 3.45×10^-19

Explanation:

Energy = hc/L

Where

h=const=6.67×10^-34

c=speed of light

L=wavelength (given)

Thr is an easier formula to that

E=12400/L(in Å)

That would give u the ans in eV

Then multiply it with 1.6×10^-19

To get ans in joules.

E=12400/6000

=2.066

~2.067eV

Hope this helps!

CHEERIO

Answer 2

Thus the energy of the photon of light is 3000 A.

Explanation:

We know, E=hv

E = energy of a quantum of radiation

h=plank's constant

u = frequency of radiation

And c = vλ

Now, E = hv = hc / λ = hc / 6000 ----- (1)

ZE =hv1 = hc / λ1 ------ (2)

Now Put in 2

Z x hc / 6000 A = hc / λ1

λ1 = 3000 A

Thus the energy of the photon of light is 3000 A.