Find out energyof electron in 2nd orbitof hydrogen gas?
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Energy of electron in the orbits of atoms is given as :-
-13.6 × z²/n² eV
Where, z = atomic number, n = number of shell.
So, Hydrogen's atomic number (z) = 1
Number of shell (n) = 2
So, energy =
-13.6 × 1²/2²
= -13.6 × 1/4
= -3.4 eV
Answer :- (-3.4) eV
Other formulas :-
» Potential energy = 2 × Energy
= 2 × -13.6 × z²/n²
» Kinetic energy = |energy|
= + 13.6 × z²/n²
» 1 eV = 1.6 × 10^(-19) Joules.
» Velocity of electron = 2.2 × 10^(6) ×(z/n)m/s
» Radius of electron = 0.529 × n²/z angstroms.
-13.6 × z²/n² eV
Where, z = atomic number, n = number of shell.
So, Hydrogen's atomic number (z) = 1
Number of shell (n) = 2
So, energy =
-13.6 × 1²/2²
= -13.6 × 1/4
= -3.4 eV
Answer :- (-3.4) eV
Other formulas :-
» Potential energy = 2 × Energy
= 2 × -13.6 × z²/n²
» Kinetic energy = |energy|
= + 13.6 × z²/n²
» 1 eV = 1.6 × 10^(-19) Joules.
» Velocity of electron = 2.2 × 10^(6) ×(z/n)m/s
» Radius of electron = 0.529 × n²/z angstroms.
shafaquenaz0308:
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Answered by
2
Answer:
Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy. If it is in the second energy level, it must have -3.4 eV of energy.
...
Energy Levels of Electrons.
Energy LevelEnergy1-13.6 eV2-3.4 eV3-1.51 eV4-.85 eV
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