find out number of molecules in 500 gram of caco 3
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Answer:
30.115 × 10^-23
Explanation:
no. of moles of CACO3 = given mass/molar mass
= 500/100
= 5
no. of moles of CACO3 = no. of molecules/Avogrado Number (NA)
5 = no. of molecules/6.023 × 10^-23
no. of molecules = 30.115 × 10^-23
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