find out number of molecules of HNO3 in 630 gram of it
Answers
Answer:-
6.022×10²⁴ molecules
Explanation:-
• Molar mass of Hydrogen (H) = 1g/mol
• Molar mass of Nitrogen (N) = 14g/mol
• Molar mass of Oxygen (O) = 16g/mol
Hence, molar mass of HNO₃ :-
= 1 + 14 + 16×3
= 15 + 48
= 63g/mol
Number of moles in 630g of HNO₃ :-
= Given Mass/Molar mass
= 630/63
= 10 moles
∴ 10 moles are present.
• Avogadro Number = 6.022×10²³
Number of molecules :-
= No of moles × Avogadro Number
= 10 × 6.022×10²³
= 60.22×10²³
= 6.022×10²⁴ molecules
Thus, 6.022×10²⁴ molecules are there in
630g of HNO₃ .
We have,
Given mass of nitric acid = 630 g
Molar mass of nitric acid (HNO_3) = 63 g
We know,
Number of molecules = No. of moles × N_A
and, No. of moles = (Given mass)/(Molar mass)
⇒ Number of molecules = (Given mass)/(Molar mass) × N_A
⇒ No. of molecules = (630 g)/(63 g) × 6.022 × 10²³
⇒ No. of molecules = 10 × 6.022 × 10²³
⇒ No. of molecules = 6.022 × 10²⁴ {answer}.