find out oxidation number of chromium in K2CR2O7 molecule
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0
Answer:
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Answered by
2
Answer:
+6
Explanation:
let's oxidation state of Cr = y
we know K has +1 and O has -2
=> 2 × (+1) + 2 × y + 7 × (-2) = 0
=> 2 + 2y -14 = 0
=> 2y = +12
=> y = +6
So oxidation state of Cr is +6
Thank you!
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