Find out squares of consecutive natural numbers from 1 to 30.
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Answer:
Formula for Sum of squares of ’n’ natural numbers :- [n(n+1)(2n+1)]/6
Where, n= the natural number till which we want to sum the squares
Here; n=30
So, sum of squares of 30 Natural numbers =>
[30*(30+1)*(2*30+1)]/6
= [ 30*31*61 ] / 6
= [ 5*31*61 ]
= 9455 Answer.
Step-by-step explanation:
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