Math, asked by Neenumadhu2008, 4 months ago

Find out squares of consecutive natural numbers from 1 to 30.​

Answers

Answered by sonamsharmanamo
2

Answer:

Formula for Sum of squares of ’n’ natural numbers :- [n(n+1)(2n+1)]/6

Where, n= the natural number till which we want to sum the squares

Here; n=30

So, sum of squares of 30 Natural numbers =>

[30*(30+1)*(2*30+1)]/6

= [ 30*31*61 ] / 6

= [ 5*31*61 ]

= 9455 Answer.

Step-by-step explanation:

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