Question

find out the amount of mg and oxygen required to form 60gm mgo.​

Answer 1

Mg = 45 g

O₂ = 15 g

Explanation:

molar mass of Mg = 24           molar mass of O₂ = 16

Reaction:

2Mg + O₂ → 2MgO

2 moles Mg and 1 mole of oxygen is required for 2 moles of MgO

2 moles of Mg = 2 × 24 = 48 g

2MgO = 2 × 24 + 16

           = 48 + 16

           = 64

48 g gives 64 g of MgO

x g will give 60 g of MgO

x = 60 × 48/64

  = 45 g of Mg

60-45 = 15 g

and 15 g of O₂.