Math, asked by RAGHUL5679, 1 year ago

Find out the area of a triangle whose sides are 50m., 78m., and 112m.?

Answers

Answered by darksnout
1
so area of triangle would be by herons formulae
s=a + b+c
_____
2
=230/2=115

so root115×115-78×115-50×115-112

calculate this on your calculator and do not forget to under root it
Answered by Anonymous
8
\bold{YOUR~SOLUTION:==>}

\bold{ In~triangle~ABC,}

\bold{Side a = 50m}
\bold{Side b = 78m}
\bold{Side c = 112m}

\bold{Semi~perimeter~(s)~of~triangle~ABC}

\bold{= (\frac{a+b+c} {2}) }
\bold{= (\frac{50+78+112}{2}) m}
\bold{=( \frac{240}{2}) m = 120 m}

\bold{Area~of~triangle~ABC }

\bold{= \sqrt{s(s-a) (s-b) (s-c)} }
\bold{= \sqrt{120(120-50)(120-78)(120-112)}m^2}
\bold{= \sqrt{ 120 × 70 × 42 × 8}m^2}
\bold{= \sqrt{ 2822400}m^2}
\bold{= 1680 m^2 } ans.

\bold{THANKS}

\bold{ Insta~id:-@shivamsinghamrajput}

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