find out the centre of mass of an isosceles triangle of Base length a and altitude b. assume that the mass of the triangle is uniformly distributed over it's area
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To locate the center of mass of the triangle, we take a strip of width dx at a distance x from the vertex of the triangle. Length of this strip can be evaluated by similar triangles as
l = x . (a/b)
Mass of the strip is dm=
ab
2M
ldx
Distance of center of mass from the vertex of the triangle is
x
CM
=
M
1
∫xdm
=∫
0
b
b
2
2x
2
dx
=
3
2
b
Hence, the center of mass of an isosceles triangle of base length a and altitude b is
3
2
b
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