if one of the zero of polynomial (a2+9)x2+13x+6a is reciprocal of the other.find the value of a
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let one zero is u and other is v.
We given that u=1/v.so vu= 1
multiplication of zeros is equal to c/a
now uv=6a/a2+9 (vu= 1)
1=6a/a2+9
a2+9=6a
a2+9-6a=0
now factories this after factories the value of
a=-3
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