Question

Find out the energy of photon of light of wavelength 6000a

Answer 1

Explanation:

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Answer 2

The energy of the photon of light is $E=3.315\times 10^{-19}\ J$.

Explanation:

Wavelength of light, $\lambda=6000\ A=6000\times 10^{-10}\ m=6\times 10^{-7}\ m$

Let E is the energy of photon of light. it is given by the formula as :

$E=\dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{6\times 10^{-7}}$

$E=3.315\times 10^{-19}\ J$

So, the energy of the photon of light is $E=3.315\times 10^{-19}\ J$. Hence, this is the required solution.

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