find out the equivalent resistance of the circuit given alongside
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Answer:
(a) R=
R
1
R
2
R
1
R
2
=(
8+8
8×8
)=4Ω
(b) I=
R
V
=
4+(
8+8
8×8
)
8
=
8
8
=1A
(c) V=IR=1×4=4V
(d) P=I
2
R=1
2
×4=4W
(e) No difference, same current flows through each element in a series circuit.
Explanation:
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