find out the expression I have given is POSITIVE or negative ????
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K^(1-x) = e^{e(1-x)} = e^{e - ex}
Log_e K = Log_e e^e = e * Log_e e = e
Find when K^(1-x) > Log_e K
e^{e- ex} > e
e^{e - e x } / e > 1
e^{e - e x - 1} > 1
e - ex - 1 > 0
e x < e - 1
x < (e -1)/e
So for 0 < x < (e-1)/e , the given expression is positive.
(e-1)/e < x < 1 , the expression is negative.
Log_e K = Log_e e^e = e * Log_e e = e
Find when K^(1-x) > Log_e K
e^{e- ex} > e
e^{e - e x } / e > 1
e^{e - e x - 1} > 1
e - ex - 1 > 0
e x < e - 1
x < (e -1)/e
So for 0 < x < (e-1)/e , the given expression is positive.
(e-1)/e < x < 1 , the expression is negative.
kvnmurty:
clik on red heart thanks above
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