find out the first 12 multiples of the following numbers-7,11,19,21,25
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Answer:
Step-by-step explanation:
SOLUTION
The multiples of 8 are 8,16,24,32…
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a=8,d=8, S15=?
Sn=n2[2a+(n−1)d]
S15=152[2(8)+(15−1)8]
=152[16+(14)(8)]
=15×1282
=960
Answered by
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Step-by-step explanation:
7=7,14,21,28,35,42
11=11,22,33,44,55
19=19,38,57,76,95,
21=21,42,63,84,105
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