Question

find out the frequency of (AabbCcDdee) if the parents are (AabbCCddEe) and (AabbccDdee) ?

Answer 1

Hi friend here is your answer

___________________________________

Each gene is independently expressed in inheritance so we can solve the problem by considering each gene separately

The parents are AabbCcddEe and AabbccDdee

1) Aa X Aa =

1/4th offsprings will have AA

1/2 offsprings will have Aa

1/4 offsprings will have aa

2) bb X bb = bb =1

3) Cc X cc = Cc =1

4) Dd X dd =

1/2 offsprings will have Dd and 1/2 will have dd

5) Ee X ee

1/2 offsprings will have Ee and 1/2 offsprings will have ee

________________________________

So AabbCcDdee = 1/2 X 1 X 1 X 1/2 X 1/2

= 1/8

= 0.125

Answer is required in % so multiply by 100

Hence 12.5%

___________________________________

Hope it helps you.............!!
#TheUsos
Down since
Day One Ish

Answer 2

Answer:Since, this is polygenic inheritance (Quantitative inheritance ). so, it should be solved individually i.e., the alleles of both the parents should cross independently and its product should correspond to the asked progeny.

here it goes…

first gene. Aa x Aa = 1/2 (0.5)that is Asked type which is, (Aa) in progeny,

2nd gene. bb x bb= 1 (1) that is Asked type which is, (bb) in progeny,

3rd gene. CC X cc= 1, (1) that is Asked type which is, (Cc) in progeny,

4th gene. Dd X dd= 1/2 (0.5) that is Asked type which is, (Dd) in progeny,

5th gene. Ee X ee= 1/2 (0.5) that is Asked type which is, (ee) in progeny.

now, multiply all result

1/2 x 1 x 1 x 1/2 x 1/2= 1/8

so, the frequency => (1/8)*100= 12.5%

PLS MARK AS BRAINLIEST