Find out the greatest number that divides 396 exactly but divides 169 to give remainder 7.
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when divides 619 should give a remainder of 7
then 619-7=612
612 will be the number that will be completely divisible
396=3×3×2×2×11
612=3×3×2×2×17
HCF=3×3×2×2=36
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