Question

Find out the kinetic energy of an electron moving with a speed of 1.2 × 10 to the power 6 m/s. Mass of electron is 9.1 × 10 to the powe -31 kg.

Answer 1

By using formula

K.E=1/2Mv^2

=1/2*9.1*10^-31*(1.2*10^6)^2

=45.5*1.2*10^-31+12

= 45.5*1.2*10^-19

=5.46 *10^-19

Answer 2

The kinetic energy of an moving electron is $6.55\times 10^{-19}\ J$

Explanation:

Given that,

Speed of the electron, $v=1.2\times 10^6\ m/s$

Mass of electron is, $m=9.1\times 10^{-31}\ kg$

To find,

Kinetic energy of an electron.

Solution,

Due to the motion of an electron, it will exhibit kinetic energy. It is given by the relation as follows :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 9.1\times 10^{-31}\times (1.2\times 10^6)^2$

$K=6.55\times 10^{-19}\ J$

So, the kinetic energy of an moving electron is $6.55\times 10^{-19}\ J$

Learn more,

Kinetic energy

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