Question

what is the speed of an apple dropped from a tree after 1.5 seconds? what distance will it cover during this time?
take
$g = \frac{10m}{ {s}^{2} }$

Answer 1

Since v=u+at

v=at

v=10×1.5

v=15 m/s

Since v^2-u^2 = 2as

v^2= 2as

15×15= 2× 10× s

s= 225/20

s=11.25 m

Answer 2

Answer:

v= u±at

u, Initial velocity of apple=0

a, acceleration due to gravity=10 m/s²

t, time = 1.5 second

v, speed of apple=?

v=0±10×1.5=15

>Speed after 1.5 sec =15m/s

Distance covered by apple:-

s=ut±1/2at²

u=0; t=1.5sec ;a=10m/s²

s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25

Distance covered by the apple=11.25m

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