Question

Find out the normality of following solution 36.5 gram of HCL in 250 ml of solution

Answer 1

Answer:4

Explanation:

Normality= n×molarity

Given,

Weight of solute=36.5gm

Molar mass of HCL= 36.5

No of Mole of solute= 36.5÷36.5= 1

Molarity= no. Of mol of solute÷ volume of solution in (litre)

1×1000÷250= 4 .

Normality factor of HCL is 1

So, normality= 1×4= 4