Question

Find out the nth Term and 12th term of the series
3/5,1/5, (-)1/5,(-)3/5
​

Answer 1

Step-by-step explanation:

d = t2-t1 = 1/5-3/5 = -2/5

= t3-t2 = -1/5-1/5 = -2/5

3/5,1/5, (-)1/5,(-)3/5. A. P.

a = 3/5. d = -2/5

an = a+(n-1)d

a12 = a+11d

= 3/5-22/5 = -19/5

Answer 2

Answer:

Step-by-step explanation:

here,a=3/5,d=1/5-3/5=-2/5

nth term(tn)=a+(n-1)d

=3/5+(-2n/5+2/5)          [d= -2/5]

=1-2n/5

and T12=3/5+(12-1)-2/5

=3/5+11×-2/5= -19/5

is thecorrect answer .

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