Question

Find out the process of oxidation, reduction oxidizing agent, reducing agent from the following:-

(a) MnO2 + 4HCl MnCl2 + 2H2O + Cl2 (b) H2S + SO2  S + H2O (c) CuO + C  Cu

+ CO

Answer 1

hello friend!

(a) MnO₂ + 4HCl ----> MnCl₂ + 2H₂O + Cl₂
Oxidised substance = HCl
Reduced substance = MnO₂
 Oxidising agent = MnO₂
Reducing agent = HCl


(b) 2H₂S + SO₂--->3S +2 H₂O ( after balancing)
Oxidised substance = SO₂
Reduced substance= H₂S
Oxidising agent= H₂S
Reducing agent= SO₂

(c) 2CuO + C ---> 2Cu ( after balancing)
Oxidised substance = Cu
Reduced substance= O₂
Oxidising agent= O₂
Reducing agent= Cu

hope it helps!

Answer 2

Answer:

Explanation:

a) MnO2 is oxidising agent which reduces to MnCl2 and HCl is reducing agent which oxidises to H2O

b)H2S is reducing agent which gets oxidised to H2O and SO2 is oxidising agent which gets reduced to S

c)CuO is oxidising agent which gets reduced to Cu and C is reducing agent and is oxidised to CO