Question

Find out the pythagoran triplet whose smallest no is 48

Answer 1

✔✔heya here is ur answer!!!

__________________________

the smallest no. is 48

i.e, 2m = 48

=> m = 24

the Pythagorean triplets are : 2m, m^2-1, m^2+1

=> m^2-1 = 24^2-1

=> 576-1

=> 575

=> m^2+1 = 24^2+1

=> 576+1

=> 577

Therefore the Pythagorean triplets are 48, 575, 577...

THANK YOU ✌✌

HOPE IT HELPS YOU ☺☺

Answer 2

heya...

Here is your answer...

Given,

The smallest number = 48

i.e. 2m = 48

m = 48/2

m = 24

=)m^2-1

= 24^2-1

= 576-1

= 575

=)m^2+1

= 24^2+1

= 576+1

= 577

Therefore the Pythagorean triplets are 48,575,577.

It may help you...☺☺