Math, asked by bhagyashreed564, 1 day ago

Find out the ratio of 1815:52978:15141​

Answers

Answered by sws1668
0

Answer:

required ratio =\frac{81}{108}=\frac{81\div27}{108\div27}=\frac{3}{4}=3:4

[HCF of 81 and 108 = 27]

Answered by himab8420
0

Answer:

SOLUTION:

i) required ratio =\frac{81}{108}=\frac{81\div27}{108\div27}=\frac{3}{4}=3:4

108

81

=

108÷27

81÷27

=

4

3

=3:4

[HCF of 81 and 108 = 27]

ii) required ratio= \frac{98}{63}=\frac{98\div7}{63\div7}=\frac{14}{9}=14:9

63

98

=

63÷7

98÷7

=

9

14

=14:9

[HCF of 98 and 63=7]

iii) required ratio = =\frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}=3:11=

121

33

=

121÷11

33÷11

=

11

3

=3:11

[HCF of 33 and 121 =11]

iv) required ratio = \frac{30}{45}=\frac{30\div15}{45\div15}=\frac{2}{3}=2:3\

45

30

=

45÷15

30÷15

=

3

2

=2:3 {HCF of 30 and 45= 15]

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