Question

find out the real and imaginary part of the complex number(2+3i/2+3i)
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Answer 1

Answer:

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Step-by-step explanation:

z=  

2i−1

3i  

20

−i  

19

 

​  

=  

2i−1

3(1)−(−i)))

​  

=  

−1+2i

3+i

​  

 

=  

−1+2i

3+i

​  

×  

−1−2i

−1−2i

​  

 

=  

(−1  

2

)+2  

2

 

−3−6i−i−2i  

2

 

​  

 

=  

5

−1−7i

​  

=  

5

−1

​  

−  

5

7

​  

i

Re(z)=−  

5

1

​  

 and Im(z)=  

5

−7

​