Question

find out the simple interest on Rs3000 at 8℅ interest rate for 3 years and also find out the total due amount after 3 years​

Answer 1

Given :

• Principal = Rs.3000
• Rate of Interest = 8%
• Time = 3 years

To find :

• the simple interest
• the total due amount

Solution :

⇒ Let's find the Simple Interest.

$\sf \longrightarrow Simple \: Interest = \dfrac{Principal \times Rate \times Time }{100}$

$\sf \longrightarrow \dfrac{3000 \times 8 \times 3}{100}$

$\sf \longrightarrow \dfrac{3000 \times 24}{100}$

$\sf \longrightarrow \dfrac{30 \not 0 \not 0 \times 24}{1 \not 0 \not 0}$

$\sf \longrightarrow \dfrac{30\times 24}{1 }$

$\sf \longrightarrow \dfrac{720}{1 }$

$\sf \longrightarrow 720$

⇒ Now, let's find the amount.

$\sf \longrightarrow Amount = Principal + Simple \: Interest$

$\sf \longrightarrow Amount = 3000 +720$

$\sf \longrightarrow Amount = 3720$

• Therefore, the simple interest is 720.
• Therefore, the amount due after 3 years is 3720.

Answer 2

Question :-

• Find the Simple Interest on Rs. 3000 at 8 % interest rate for 3 years. Also find the total Amount .

Answer :-

• Simple Interest is Rs. 720
• The Amount is Rs. 3720

$\rule {180pt} {2pt}$

Given :-

• Principal = Rs. 3000
• Rate of Interest = 8 %
• Time Period = 3 years

To Find :-

• Simple Interest = ?
• Amount = ?

Solution :-

As per the provided information in the given question, we have been given that the Principal is Rs. 3000 , Rate of Interest is given 8 % , Time Period is also given as 3 years . And we have been asked to calculate the Simple Interest and the Amount .

Formula Required :-

$\bigstar \: \: \: \boxed { \sf { \: Simple \: Interest \: = \: \frac{P \times R \times T}{100} \: }}$

$\bigstar \: \: \: \boxed{ \sf { \: Amount \: = \: P \: + \: S.I \: }}$

Where ,

• P denotes to Principal
• R denotes to Rate of Interest
• T denotes to Time Period
• S.I denotes to Simple Interest

First we will find the Simple Interest . By substituting the values in the First Formula :-

$\longmapsto \: \: \sf{Simple \: Interest \: = \: \dfrac{P \times R \times T}{100} }$

$\longmapsto \: \: \sf{Simple \: Interest \: = \: \dfrac{3000 \times 8 \times 3}{100} }$

$\longmapsto \: \: \sf{Simple \: Interest \: = \: \dfrac{30 \: \cancel{00} \times 8 \times 3}{1 \: \cancel{00}} }$

$\longmapsto \: \: \sf{Simple \: Interest \: = \: 30 \times 8 \times 3}$

$\longmapsto \: \: \textbf { \textsf {{Simple \: Interest \: = \: 720}}}$

Now we will find the Amount . By substituting the values in the Second Formula :-

$\longmapsto \: \: \sf{Amount \: = \: P \: + \: S.I}$

$\longmapsto \: \: \sf{Amount \: = \: 3000 \: + \: 720}$

$\longmapsto \: \: \textbf { \textsf {Amount \: = \: 3720}}$

Hence :-

• Simple Interest = Rs. 720
• Amount = Rs. 3720

$\rule {180pt} {4pt}$

Learn More :-

$\bigstar \: \: \: \boxed {\sf { \: \: Principal \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Rate \: \times \: Time \: \: }}}$

$\bigstar \: \: \: \boxed {\sf { \: \: Rate \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Principal \: \times \: Time \: \: }}}$

$\bigstar \: \: \: \boxed {\sf { \: \: Time \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Principal \: \times \: Rate \: \: }}}$