Question

Find out the sum of all natural numbers between 1 and 145 which are divisible by 4 .
plzz answer fast

Answer 1

Answer:in arithmatic progression

4,8,12,.........144

An= a+(n-1) d

144 = 4+(n-1)4 or n=38

Sn= n/2 [2a+(n-1)d]

=38/2 [2*4 +(38-1)4]

Sn=19*1164=22116

Answer 2

if wrong plz tell me