Question

find out the value of k when the quadratic equation x^-2kx+5k=0

Answer 1

K = 0
By using discriminant
We get
4k(k-5)=0

Answer 2

Answer:

k = 5

Step-by-step explanation:

x² - 2kx + 5k = 0

Given that it has equal roots

⇒ b² - 4ac = 0

Solve k:

b² - 4ac = =0

(-2k)² - 4(1)(5k) = 0

4k²  - 20k = 0

k²  - 5k = 0

k(k - 5) = 0

k = 0 or k - 5 = 0

k = 0 or k = 5

Since k = 0 will make the equation not a quadratic equation

⇒ k is rejected

Therefore k = 5

Answer: k = 5