Question

Find out two third life of a first order reaction in which K is equal to 5.48 × 10‐¹⁴second inverse​

Answer 1

Explanation:

tn=k2.303log[A][A0]

Let, 

[A]0=a

[A]=a−32a=3a

Therefore, 

t2/3=5.48×10−142.303log(3a)a=2.0×1013s

Answer 2

Answer:

• this is the required answer