find oxidation number of nitrogen in the following compounds
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1...N2O -->2x+(-2)=0
x=1
2...NO. -->x-2=0. so x=2
3...NO2 -->x-4=0
x=4
hope it helps
x=1
2...NO. -->x-2=0. so x=2
3...NO2 -->x-4=0
x=4
hope it helps
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