Question

Find oxidation state [Cu (NH3)4] So4​

Answer 1

In [ Cu ( NH3)4]SO4 , the oxidation number of NH3 is zero (0) because the ammonia molecule is a neutral molecule . On the other hand the oxidation number of SO4 ion is –2 .

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Answer 2

The oxidation state of Cu in $\[[Cu{(N{H_3})_4}]S{O_4}\]$  is $+2$.  

Explanation:

• In the given complex, $\[N{H_3}\]$ has zero charge.
• Sulphate ion has $-2$ charge.
• Therefore, to make the complex neutral, copper must have $+2$ charge.
• Thus, the oxidation state of Cu in $\[[Cu{(N{H_3})_4}]S{O_4}\]$ is $+2$.