Math, asked by pradnyabhosle79, 4 months ago

find P(0) and P(-2) for P(x)=(y+2)(y-2)

Answers

Answered by mayabk

1

Answer:

p(0)=(0+2)(0-2)

=2(-2)

=-4

p(-2)=(-2+2)(-2-2)

=0(-4)

=0

Answered by pinkyshukla743

0

Answer:

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