Question

find p(0) for the following polynomial 1- p(y)=y^2-y+1

Answer 1

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P(Y) = Y² - Y + 1


P(0) = (0)² - 0 + 1 = 0-0+1 = 1



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Answer 2

P(y) = y² - y + 1

P(0) = 0² - 0 + 1

P(0) = 0 - 0 + 1

P(0) = 1