find p(0) if p(y) =ysquare -y+1
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p (0)=y square -y+1
= (0)square -0+1
=0-0+1
=1
= (0)square -0+1
=0-0+1
=1
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Answered by
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see,
p(y)=p(0),then y=0.
now,
y^2-y+1=0^2+0+1
=0+0+1
=1.
hope this helps you.....
p(y)=p(0),then y=0.
now,
y^2-y+1=0^2+0+1
=0+0+1
=1.
hope this helps you.....
tks
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