Question

find p(0),p(1)&p(2) for p(x)=x²‐x+1
answer me fast ​

Answer 1

Answer:

p(0) =1

p(1) = 1

p(2)=3

Step-by-step explanation:

$p(0) = (0)^{2}-(0)+1\\ 0-0+1\\=>1\\\\p(1) = (1)^{2}-(1)+1\\ 1-1+1\\=>1\\\\p(2) = (2)^{2}-(2)+1\\4-2+1\\ =>3$