Question

Find p(0);p(1) and p(2) for each of the following polynomials 1 . P(x)=x2-x+1

Answer 1

Answer:

Given,

p(x) = x²-x-1

p(0) = (0)²-(0)-1

= -1

p(1) = (1)²-(1)-1

= 1-1-1

= 1-2

= -1

p(2) = (2)²-(2)-1

= 4-2-1

= 4-3

= 1

p(0) = -1

p(1) = -1

p(2) = 1

hope it helps.... ☺

Answer 2

Answer:

P(x)=x^2-x+1

P(0)=0-0+1

p(0)=1

P(1)= (1)^2-1+1

P(1)=1

P(2)=(2)^2-2+1

P(2)=4-2+1

P(2)=3

Hope it helps.......