Question

Find p(0),p(1) and p(2) for each of the following polynomials.
(1) P(x) = x2-x+1
(i) p()= 2 + y + 2y2 - y
(i) P(z)=z3
(iv) p() = (t-1) (t+1)
(v) P(x)= x2 – 3x + 2​

Answer 1

here is your answer

For p (0),

p (y)=2y^2-3y+2

p(o) =2 (o)^2-3(o)+2

p(o)=2

Now for p (1),

p(y)=2y^2-3y+2

p(1)=2(1)^2-3(1)+2

p(1) =1

finally for p(2),

p(2)=2y^2-3y+2

p(2)=3